# NCERT Solutions Of Class 8 Maths Chapter 5 Data Handling

## Introduction

**Class 8 Maths Exercise 5.3 (Page-82)**

**Q1. **List the outcomes you can see in these experiments.

(i) Spinning a wheel

(ii) Tossing two coins together

**Solution: **

**i) **There will be 4 outcomes i.e. A, B, C, D.

**ii) **HT, TH, HH, TT

**Q2. **When a die is thrown, list the outcomes of an event of getting

(i) (a) a prime number

(b) not a prime number

(ii) (a) a number greater than 5

(b) a number not greater than 5

**Solution: **

**i)(a)** 2,3 and 5 are the prime number.

**i)(b) **1,4 and 6 are not prime number.

**ii)(a) **6 is the number greater than 5.

**ii)(b) **1,2,3,4 and 5 are the number not greater than 5.

**Q3. **Find the

(i) Probability of the pointer stopping on D in (Question 1-(a))

(ii) Probability of getting an ace from a well-shuffled deck of 52 playing cards?

(iii) Probability of getting a red apple, (see figure below)

**Solution: **

**i)** Probability = \(\displaystyle \frac{{Number\,of\,outcomes}}{{Total\,number\,of\,outcomes}}\)

= \(\displaystyle \frac{1}{5}\)

So, the Probability of the pointer stopping on D in (Question 1-(a)) is \(\displaystyle \frac{1}{5}\)

**ii) **Probability = \(\displaystyle \frac{{Number\,of\,outcomes}}{{Total\,number\,of\,outcomes}}\)

= \(\displaystyle \frac{4}{52}\)

= \(\displaystyle \frac{1}{13}\)

So, the Probability of getting an ace from a well-shuffled deck of 52 playing cards is \(\displaystyle \frac{1}{13}\)

**iii) **Probability = \(\displaystyle \frac{{Number\,of\,outcomes}}{{Total\,number\,of\,outcomes}}\)

= \(\displaystyle \frac{4}{7}\)

So, the probability of getting a red apple is \(\displaystyle \frac{4}{7}\)

**Q4. **Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is choosen from the box without looking into it. What is the probability of:

(i) getting a number 6?

(ii) getting a number less than 6?

(iii) getting a number greater than 6?

(iv) getting a 1-digit number?

**Solution: **

**i) **Probability = \(\displaystyle \frac{{Number\,of\,outcomes}}{{Total\,Number\,of\,Outcomes}}\)

=\(\displaystyle \frac{1}{{10}}\)

So, the probability of getting a number 6 is \(\displaystyle \frac{1}{{10}}\).

**ii) **Number less than 6 are 5,4,3,2 and 1.

** **Probability = \(\displaystyle \frac{{Number\,of\,outcomes}}{{Total\,Number\,of\,Outcomes}}\)

=\(\displaystyle \frac{5}{{10}}\)

= \(\displaystyle \frac{1}{{2}}\)

So, the probability of getting a number less than 6 is \(\displaystyle \frac{1}{{2}}\)

**iii) **** ** number greater than 6 are 7,8,9 and 10. So,

Probability = \(\displaystyle \frac{{Number\,of\,outcomes}}{{Total\,Number\,of\,Outcomes}}\)

=\(\displaystyle \frac{4}{{10}}\)

=\(\displaystyle \frac{2}{{5}}\)

So, the probability of getting a number greater than 6 is \(\displaystyle \frac{2}{{5}}\).

**iv) **Number of 1 digit numbers are 9.

** **Probability = \(\displaystyle \frac{{Number\,of\,outcomes}}{{Total\,Number\,of\,Outcomes}}\)

=\(\displaystyle \frac{9}{{10}}\)

So, the probability of getting a 1-digit number is \(\displaystyle \frac{9}{{10}}\).

**Q5. **If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non-blue sector?

**Solution: **

**Q6. **Find the probabilities of the events given in Question 2.

**Solution: **