NCERT Solutions Class 9 Maths Chapter 10 Heron's Formula
Introduction:
In this chapter we will learn about Heron's Formula. You have studied the following points :
- Area of a triangle with its sides as a, b and c is calculated by using Heron's Formula, stated as Area of a triangle = \(\displaystyle \sqrt{{s\,(\,s\,-\,a\,)\,(\,s\,-\,b\,)\,(\,s\,-\,c\,)}}\)
where S = \(\displaystyle \frac{{a\,+\,b\,+\,c}}{2}\)
2. Area of a quadrilateral whose sides and one diagonal are given, cab be calculated by dividing the quadrilateral into two triangles and using Heron's Formula.
3.Unit of measurement for length or breadth is taken as meter ( m ) or centimeter ( cm ) etc.
4. Unit of measurement for area of any plane figure is taken as square meter ( m2 ) or centimeter ( cm2 ) etc.
NCERT Class 9 Maths Chapter 10 Heron's Formula :
NCERT Solutions Class 9 Maths Chapter 10 Heron's Formula Exercise 10.1
In this exercise-10.1 we will learn about Heron's Formula. We know you have studied in earlier classes about area of triangle and perimeter but in this chapter different types of formulae you will learn in the chapter. Perimeter of the triangle = \(\displaystyle \frac{{a\,+\,b\,+\,c}}{2}\) and Area of a triangle = \(\displaystyle \sqrt{{s\,(\,s\,-\,a\,)\,(\,s\,-\,b\,)\,(\,s\,-\,c\,)}}\) .
NCERT Class 9 Maths Chapter 10 Heron's Formula :